ចំណាំៈ ការប្រើ Number Key គឺប្រើនៅខាងស្តាំ នៃផ្នែក Keyboard ។
Sunday, August 6, 2017
របៀបបង្កើត Folder ដោយគ្មានឈ្មោះ
ចំណាំៈ ការប្រើ Number Key គឺប្រើនៅខាងស្តាំ នៃផ្នែក Keyboard ។
Thursday, October 29, 2015
Cartoon HD ងាយស្រួលមើល Movies online (Smartphone)
កម្មវិធី Cartoon HD គឺជាកម្មវិធីដែលមានភាពងាយស្រួលមើលភាពយន្ដនៅលើ internet ហើយយើងក៏អាចធ្វើការដោនឡូតបានផងដែរ ។ កម្មវិធីនេះវាមានការ update នូវរឿងថ្មីៗ រឿងចាស់ ជាច្រើន ដែលយើងចង់មើល ។
សម្រាប់ iPhone, iPad, or iPod Touch សូមមើលតំណភ្ជាប់នេះ Cartoon HD
Enjoy !!!!!!!
Download for Android
សម្រាប់ iPhone, iPad, or iPod Touch សូមមើលតំណភ្ជាប់នេះ Cartoon HD
Enjoy !!!!!!!
Friday, June 5, 2015
Cisco Before Subnet (Video)
Example: 192.168.1.0/24
BEFORE SUBNET:
Network Address: 192.168.1.0
Broadcast Address: 192.168.1.255
Host Address Range: 192.168.1.1 --> 192.168.1.254
Subnet Mask: 255.255.255.0
Usable Host Addresses: 2^h - 2 = 2^8 - 2 = 254
-------------------------------
* Subnetting:
- Number of subnets = 2^s
(s: Represent number of bits borrowed from host portion)
- Number of hosts per subnet = 2^h - 2
(h: Represent number of bits left in host portion)
==============================
AFTER SUBNET: 192.168.1.0/24 ----> /26
Procedure:
Step 1: Check bit location in which octet, in this example: /26 is in octet 4
Step 2: Take the max bit in octet 4 to minus it
32 - 26 = 6 bits
Step 3: Take 2^6bits = 64
Step 4: We get 4 subnets
Subnet 0 : 192.168.1.0/26
Subnet 1 : 192.168.1.64/26
Subnet 2 : 192.168.1.128/26
Subnet 3 : 192.168.1.192/26
==========================
IP Characteristic:
- Decimal dotted notation
- Have 4 octets (1 octet = 8 bits)
- Bit range is 32 bits
- Separate into 2 portions
Network portion | Host portion
ex: 8bits | ---> 24bits
---> 24bits | 7bits
=============================
*** Have 5 Classes as below: (Actually, we use 3 classes in the network everyday)
1) Class A: check octet 1, if 1 ---> 126,
Default Subnet Mask: 255.0.0.0 = or /8
Ex: IP address 11.192.180.255
2) Class B: check octet 1, if 128 ---> 191,
Default Subnet Mask: 255.255.0.0 = or /16
Ex: IP address 180.192.11.255
3) Class C: check octet 1, if 192 ---> 223,
Default Subnet Mask: 255.255.255.0 = or /24
Ex: IP address 192.11.180.0
4) Class D: check octet 1, if 224 ---> 239,
This is for network system used Multicast process.
5) Class E: check octet 1, if 240 ---> 255,
This is for experience used.
=============================
*** Divide into 2 type used:
- Private IP of Class A: 10.0.0.0 ---> 10.255.255.255 (10.0.0.0/8)
- Private IP of Class B: 172.16.0.0 ---> 172.31.255.255 (172.16.0.0/12)
- Private IP of Class C: 192.168.0.0 ---> 192.168.255.255 (192.168.0.0/16)
==============================================
Example: 192.168.1.130/25
Network Address:?
Broadcast Address:?
Host Address Range:?
Subnet Mask:?
Usable Host Addresses:?
-------------------------------
Procedure:
Step 1: Check bit location in which octet, in this example: /25 is in octet 4
Step 2: Take the number of IP in octet 4 convert to binary
130 = 10000010
Step 3: Split bit between network portion and host portion.
Represent bit 0 in host portion to get the Network Address.
Represent bit 1 in host portion to get the Broadcast Address
1 | 0000010
| 0000000 : ---> Network Address
| 111111 : ---> Broadcast Address
Step 4: Convert to decimal to get the IP.
Network Address: 192.168.1.128
Broadcast Address: 192.168.1.255
Step 5: Host address range is started from higher 1 value of Network address till lower 1 value of Broadcast address.
Host Address Range: 192.168.1.129 ---> 192.168.1.254
Step 6: In this example is /25 mean bit 1 = 25 in network portion
/25 = 11111111.11111111.11111111.10000000
255 . 255 . 255 . 128
Subnet Mask: 255.255.255.128
Step 7: Number of usable host addresses 2^h -2 (h : represent number of bits in host portion)
In this example, h = 7 bits
2^7 - 2 = 126
Usable Host Addresses: 126
BEFORE SUBNET:
Network Address: 192.168.1.0
Broadcast Address: 192.168.1.255
Host Address Range: 192.168.1.1 --> 192.168.1.254
Subnet Mask: 255.255.255.0
Usable Host Addresses: 2^h - 2 = 2^8 - 2 = 254
-------------------------------
* Subnetting:
- Number of subnets = 2^s
(s: Represent number of bits borrowed from host portion)
- Number of hosts per subnet = 2^h - 2
(h: Represent number of bits left in host portion)
==============================
AFTER SUBNET: 192.168.1.0/24 ----> /26
Procedure:
Step 1: Check bit location in which octet, in this example: /26 is in octet 4
Step 2: Take the max bit in octet 4 to minus it
32 - 26 = 6 bits
Step 3: Take 2^6bits = 64
Step 4: We get 4 subnets
Subnet 0 : 192.168.1.0/26
Subnet 1 : 192.168.1.64/26
Subnet 2 : 192.168.1.128/26
Subnet 3 : 192.168.1.192/26
==========================
IP Characteristic:
- Decimal dotted notation
- Have 4 octets (1 octet = 8 bits)
- Bit range is 32 bits
- Separate into 2 portions
Network portion | Host portion
ex: 8bits | ---> 24bits
---> 24bits | 7bits
=============================
*** Have 5 Classes as below: (Actually, we use 3 classes in the network everyday)
1) Class A: check octet 1, if 1 ---> 126,
Default Subnet Mask: 255.0.0.0 = or /8
Ex: IP address 11.192.180.255
2) Class B: check octet 1, if 128 ---> 191,
Default Subnet Mask: 255.255.0.0 = or /16
Ex: IP address 180.192.11.255
3) Class C: check octet 1, if 192 ---> 223,
Default Subnet Mask: 255.255.255.0 = or /24
Ex: IP address 192.11.180.0
4) Class D: check octet 1, if 224 ---> 239,
This is for network system used Multicast process.
5) Class E: check octet 1, if 240 ---> 255,
This is for experience used.
=============================
*** Divide into 2 type used:
- Private IP of Class A: 10.0.0.0 ---> 10.255.255.255 (10.0.0.0/8)
- Private IP of Class B: 172.16.0.0 ---> 172.31.255.255 (172.16.0.0/12)
- Private IP of Class C: 192.168.0.0 ---> 192.168.255.255 (192.168.0.0/16)
==============================================
Example: 192.168.1.130/25
Network Address:?
Broadcast Address:?
Host Address Range:?
Subnet Mask:?
Usable Host Addresses:?
-------------------------------
Procedure:
Step 1: Check bit location in which octet, in this example: /25 is in octet 4
Step 2: Take the number of IP in octet 4 convert to binary
130 = 10000010
Step 3: Split bit between network portion and host portion.
Represent bit 0 in host portion to get the Network Address.
Represent bit 1 in host portion to get the Broadcast Address
1 | 0000010
| 0000000 : ---> Network Address
| 111111 : ---> Broadcast Address
Step 4: Convert to decimal to get the IP.
Network Address: 192.168.1.128
Broadcast Address: 192.168.1.255
Step 5: Host address range is started from higher 1 value of Network address till lower 1 value of Broadcast address.
Host Address Range: 192.168.1.129 ---> 192.168.1.254
Step 6: In this example is /25 mean bit 1 = 25 in network portion
/25 = 11111111.11111111.11111111.10000000
255 . 255 . 255 . 128
Subnet Mask: 255.255.255.128
Step 7: Number of usable host addresses 2^h -2 (h : represent number of bits in host portion)
In this example, h = 7 bits
2^7 - 2 = 126
Usable Host Addresses: 126
Cisco After Subnet (Video)
Example: 192.168.1.0/24
BEFORE SUBNET:
Network Address: 192.168.1.0
Broadcast Address: 192.168.1.255
Host Address Range: 192.168.1.1 --> 192.168.1.254
Subnet Mask: 255.255.255.0
Usable Host Addresses: 2^h - 2 = 2^8 - 2 = 254
-------------------------------
* Subnetting:
- Number of subnets = 2^s
(s: Represent number of bits borrowed from host portion)
- Number of hosts per subnet = 2^h - 2
(h: Represent number of bits left in host portion)
==============================
AFTER SUBNET: 192.168.1.0/24 ----> /26
Procedure:
Step 1: Check bit location in which octet, in this example: /26 is in octet 4
Step 2: Take the max bit in octet 4 to minus it
32 - 26 = 6 bits
Step 3: Take 2^6bits = 64
Step 4: We get 4 subnets
Subnet 0 : 192.168.1.0/26
Subnet 1 : 192.168.1.64/26
Subnet 2 : 192.168.1.128/26
Subnet 3 : 192.168.1.192/26
==========================
IP Characteristic:
- Decimal dotted notation
- Have 4 octets (1 octet = 8 bits)
- Bit range is 32 bits
- Separate into 2 portions
Network portion | Host portion
ex: 8bits | ---> 24bits
---> 24bits | 7bits
=============================
*** Have 5 Classes as below: (Actually, we use 3 classes in the network everyday)
1) Class A: check octet 1, if 1 ---> 126,
Default Subnet Mask: 255.0.0.0 = or /8
Ex: IP address 11.192.180.255
2) Class B: check octet 1, if 128 ---> 191,
Default Subnet Mask: 255.255.0.0 = or /16
Ex: IP address 180.192.11.255
3) Class C: check octet 1, if 192 ---> 223,
Default Subnet Mask: 255.255.255.0 = or /24
Ex: IP address 192.11.180.0
4) Class D: check octet 1, if 224 ---> 239,
This is for network system used Multicast process.
5) Class E: check octet 1, if 240 ---> 255,
This is for experience used.
=============================
*** Divide into 2 type used:
- Private IP of Class A: 10.0.0.0 ---> 10.255.255.255 (10.0.0.0/8)
- Private IP of Class B: 172.16.0.0 ---> 172.31.255.255 (172.16.0.0/12)
- Private IP of Class C: 192.168.0.0 ---> 192.168.255.255 (192.168.0.0/16)
==============================================
Example: 192.168.1.130/25
Network Address:?
Broadcast Address:?
Host Address Range:?
Subnet Mask:?
Usable Host Addresses:?
-------------------------------
Procedure:
Step 1: Check bit location in which octet, in this example: /25 is in octet 4
Step 2: Take the number of IP in octet 4 convert to binary
130 = 10000010
Step 3: Split bit between network portion and host portion.
Represent bit 0 in host portion to get the Network Address.
Represent bit 1 in host portion to get the Broadcast Address
1 | 0000010
| 0000000 : ---> Network Address
| 111111 : ---> Broadcast Address
Step 4: Convert to decimal to get the IP.
Network Address: 192.168.1.128
Broadcast Address: 192.168.1.255
Step 5: Host address range is started from higher 1 value of Network address till lower 1 value of Broadcast address.
Host Address Range: 192.168.1.129 ---> 192.168.1.254
Step 6: In this example is /25 mean bit 1 = 25 in network portion
/25 = 11111111.11111111.11111111.10000000
255 . 255 . 255 . 128
Subnet Mask: 255.255.255.128
Step 7: Number of usable host addresses 2^h -2 (h : represent number of bits in host portion)
In this example, h = 7 bits
2^7 - 2 = 126
Usable Host Addresses: 126
BEFORE SUBNET:
Network Address: 192.168.1.0
Broadcast Address: 192.168.1.255
Host Address Range: 192.168.1.1 --> 192.168.1.254
Subnet Mask: 255.255.255.0
Usable Host Addresses: 2^h - 2 = 2^8 - 2 = 254
-------------------------------
* Subnetting:
- Number of subnets = 2^s
(s: Represent number of bits borrowed from host portion)
- Number of hosts per subnet = 2^h - 2
(h: Represent number of bits left in host portion)
==============================
AFTER SUBNET: 192.168.1.0/24 ----> /26
Procedure:
Step 1: Check bit location in which octet, in this example: /26 is in octet 4
Step 2: Take the max bit in octet 4 to minus it
32 - 26 = 6 bits
Step 3: Take 2^6bits = 64
Step 4: We get 4 subnets
Subnet 0 : 192.168.1.0/26
Subnet 1 : 192.168.1.64/26
Subnet 2 : 192.168.1.128/26
Subnet 3 : 192.168.1.192/26
==========================
IP Characteristic:
- Decimal dotted notation
- Have 4 octets (1 octet = 8 bits)
- Bit range is 32 bits
- Separate into 2 portions
Network portion | Host portion
ex: 8bits | ---> 24bits
---> 24bits | 7bits
=============================
*** Have 5 Classes as below: (Actually, we use 3 classes in the network everyday)
1) Class A: check octet 1, if 1 ---> 126,
Default Subnet Mask: 255.0.0.0 = or /8
Ex: IP address 11.192.180.255
2) Class B: check octet 1, if 128 ---> 191,
Default Subnet Mask: 255.255.0.0 = or /16
Ex: IP address 180.192.11.255
3) Class C: check octet 1, if 192 ---> 223,
Default Subnet Mask: 255.255.255.0 = or /24
Ex: IP address 192.11.180.0
4) Class D: check octet 1, if 224 ---> 239,
This is for network system used Multicast process.
5) Class E: check octet 1, if 240 ---> 255,
This is for experience used.
=============================
*** Divide into 2 type used:
- Private IP of Class A: 10.0.0.0 ---> 10.255.255.255 (10.0.0.0/8)
- Private IP of Class B: 172.16.0.0 ---> 172.31.255.255 (172.16.0.0/12)
- Private IP of Class C: 192.168.0.0 ---> 192.168.255.255 (192.168.0.0/16)
==============================================
Example: 192.168.1.130/25
Network Address:?
Broadcast Address:?
Host Address Range:?
Subnet Mask:?
Usable Host Addresses:?
-------------------------------
Procedure:
Step 1: Check bit location in which octet, in this example: /25 is in octet 4
Step 2: Take the number of IP in octet 4 convert to binary
130 = 10000010
Step 3: Split bit between network portion and host portion.
Represent bit 0 in host portion to get the Network Address.
Represent bit 1 in host portion to get the Broadcast Address
1 | 0000010
| 0000000 : ---> Network Address
| 111111 : ---> Broadcast Address
Step 4: Convert to decimal to get the IP.
Network Address: 192.168.1.128
Broadcast Address: 192.168.1.255
Step 5: Host address range is started from higher 1 value of Network address till lower 1 value of Broadcast address.
Host Address Range: 192.168.1.129 ---> 192.168.1.254
Step 6: In this example is /25 mean bit 1 = 25 in network portion
/25 = 11111111.11111111.11111111.10000000
255 . 255 . 255 . 128
Subnet Mask: 255.255.255.128
Step 7: Number of usable host addresses 2^h -2 (h : represent number of bits in host portion)
In this example, h = 7 bits
2^7 - 2 = 126
Usable Host Addresses: 126
Sunday, December 14, 2014
Microsoft Dot NET Framework All Version
Microsoft .NET Framework គឺជា Framework មួយដ៏មានសារៈសំខាន់ ដែលត្រូវបាន ក្រុមហ៊ុន Microsoft បង្កើតឡើងដែលដំណើរការនៅក្នុង Microsoft Windows ។ ហើយវាត្រូវបានរួមបញ្ចូលនូវ Library ដ៏ធំនិងផ្ដល់នូវអន្តរប្រតិបត្តិការទូទាំងភាសាសរសេរកម្មវិធីមួយចំនួន។ ការសរសេរកម្មវិធីផលិតកម្មវិធី software ដោយការរួមបញ្ចូលគ្នារវាងSource Code ជាមួយនឹង Dot NET Framework និង Library ដទៃទៀត។ Microsoft Dot NET Framework គឺត្រូវបានបម្រុងទុកដើម្បីប្រើជាមួយកម្មវិធីថ្មីបំផុតដែលបានបង្កើតសម្រាប់ប្រព័ន្ធវីនដូ។
Friday, December 12, 2014
ផ្ទុកឯកសាររហូតដល់ 36TB ជាមួយ 360 Cloud Disk
សម័យបច្ចុប្បន្ននេះ បច្ចេកវិទ្យាកាន់តែរីកចម្រើនទៅៗ ដែលធ្វើឲ្យពិភពលោកយើងនេះកាន់តែទំនើប ។ ហើយចំពោះការផ្ទុកឯកសារ គឺត្រូវបានគេនិយមប្រើជាមួយ Cloud Computer ឬហៅម្យ៉ាងទៀតថា Online Storage ។ ឥឡូវនេះខ្ញុំសូមណែនាំនូវ Online Storage មួយដែលជនជាតិចិននិយមប្រើ គឺ 360 Storage ។ ចំពោះការផ្ទុករបស់វាគឺមានទំហំរហូតដល់ ទៅ 36TB ដែលជាទំហំមិនគួរឲ្យជឿ ប៉ុន្ដែខ្ញុំបានប្រើវាហើយ គឺវាមានទំហំរហូតដល់ 36TB ពិតមែន ។ សូមចុចទីនេះដើម្បីចុះឈ្មោះ 360 Online Storage
ប៉ុន្ដែដើម្បីឲ្យបានគ្រប់ 36TB លោកអ្នកត្រូវ install វាទៅក្នុងទូរសព្ទ ។ បើមិនទាន់ Install ក្នុងទូរសព្ទគឺវាផ្ដល់ជូនត្រឹមតែ 10TB ប៉ុណ្ណោះ ។
ប៉ុន្ដែដើម្បីឲ្យបានគ្រប់ 36TB លោកអ្នកត្រូវ install វាទៅក្នុងទូរសព្ទ ។ បើមិនទាន់ Install ក្នុងទូរសព្ទគឺវាផ្ដល់ជូនត្រឹមតែ 10TB ប៉ុណ្ណោះ ។
